3.995 \(\int \frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{a+i a \tan (e+f x)}} \, dx\)

Optimal. Leaf size=41 \[ \frac{i \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}} \]

[Out]

(I*Sqrt[c - I*c*Tan[e + f*x]])/(f*Sqrt[a + I*a*Tan[e + f*x]])

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Rubi [A]  time = 0.0955962, antiderivative size = 41, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.057, Rules used = {3523, 37} \[ \frac{i \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[c - I*c*Tan[e + f*x]]/Sqrt[a + I*a*Tan[e + f*x]],x]

[Out]

(I*Sqrt[c - I*c*Tan[e + f*x]])/(f*Sqrt[a + I*a*Tan[e + f*x]])

Rule 3523

Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist
[(a*c)/f, Subst[Int[(a + b*x)^(m - 1)*(c + d*x)^(n - 1), x], x, Tan[e + f*x]], x] /; FreeQ[{a, b, c, d, e, f,
m, n}, x] && EqQ[b*c + a*d, 0] && EqQ[a^2 + b^2, 0]

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rubi steps

\begin{align*} \int \frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{a+i a \tan (e+f x)}} \, dx &=\frac{(a c) \operatorname{Subst}\left (\int \frac{1}{(a+i a x)^{3/2} \sqrt{c-i c x}} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{i \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}}\\ \end{align*}

Mathematica [A]  time = 1.13828, size = 41, normalized size = 1. \[ \frac{i \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[c - I*c*Tan[e + f*x]]/Sqrt[a + I*a*Tan[e + f*x]],x]

[Out]

(I*Sqrt[c - I*c*Tan[e + f*x]])/(f*Sqrt[a + I*a*Tan[e + f*x]])

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Maple [A]  time = 0.115, size = 65, normalized size = 1.6 \begin{align*}{\frac{-i \left ( 1+i\tan \left ( fx+e \right ) \right ) }{fa \left ( -\tan \left ( fx+e \right ) +i \right ) ^{2}}\sqrt{-c \left ( -1+i\tan \left ( fx+e \right ) \right ) }\sqrt{a \left ( 1+i\tan \left ( fx+e \right ) \right ) }} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c-I*c*tan(f*x+e))^(1/2)/(a+I*a*tan(f*x+e))^(1/2),x)

[Out]

-I/f*(-c*(-1+I*tan(f*x+e)))^(1/2)*(a*(1+I*tan(f*x+e)))^(1/2)/a*(1+I*tan(f*x+e))/(-tan(f*x+e)+I)^2

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Maxima [A]  time = 1.72384, size = 47, normalized size = 1.15 \begin{align*} \frac{i \, \sqrt{c} \sqrt{-i \, \tan \left (f x + e\right ) + 1}}{\sqrt{a} f \sqrt{i \, \tan \left (f x + e\right ) + 1}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c-I*c*tan(f*x+e))^(1/2)/(a+I*a*tan(f*x+e))^(1/2),x, algorithm="maxima")

[Out]

I*sqrt(c)*sqrt(-I*tan(f*x + e) + 1)/(sqrt(a)*f*sqrt(I*tan(f*x + e) + 1))

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Fricas [B]  time = 1.34277, size = 223, normalized size = 5.44 \begin{align*} \frac{\sqrt{\frac{a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}{\left (-i \, e^{\left (3 i \, f x + 3 i \, e\right )} + i \, e^{\left (2 i \, f x + 2 i \, e\right )} - i \, e^{\left (i \, f x + i \, e\right )} + i\right )} e^{\left (-i \, f x - i \, e\right )}}{a f} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c-I*c*tan(f*x+e))^(1/2)/(a+I*a*tan(f*x+e))^(1/2),x, algorithm="fricas")

[Out]

sqrt(a/(e^(2*I*f*x + 2*I*e) + 1))*sqrt(c/(e^(2*I*f*x + 2*I*e) + 1))*(-I*e^(3*I*f*x + 3*I*e) + I*e^(2*I*f*x + 2
*I*e) - I*e^(I*f*x + I*e) + I)*e^(-I*f*x - I*e)/(a*f)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{- c \left (i \tan{\left (e + f x \right )} - 1\right )}}{\sqrt{a \left (i \tan{\left (e + f x \right )} + 1\right )}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c-I*c*tan(f*x+e))**(1/2)/(a+I*a*tan(f*x+e))**(1/2),x)

[Out]

Integral(sqrt(-c*(I*tan(e + f*x) - 1))/sqrt(a*(I*tan(e + f*x) + 1)), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{-i \, c \tan \left (f x + e\right ) + c}}{\sqrt{i \, a \tan \left (f x + e\right ) + a}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c-I*c*tan(f*x+e))^(1/2)/(a+I*a*tan(f*x+e))^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(-I*c*tan(f*x + e) + c)/sqrt(I*a*tan(f*x + e) + a), x)